tolong bantuannya kak utk nmor yg paling atas
tpi klo kka nya baik dan klo tdk merepotkan blh tolong bantu jwb yg dibawahnya kk:)
beserta cara menghitunya
[tex]1. \: 2 \sqrt{8} \times \sqrt{3} [/tex]
[tex] = 2 \times 2 \sqrt{2} \sqrt{3} [/tex]
[tex] = 4 \sqrt{2} \sqrt{3} [/tex]
[tex] = 4 \sqrt{2 \times 3} [/tex]
[tex] = 4 \sqrt{6} [/tex]
[tex]2. \: \sqrt{32} - \sqrt{2} + \sqrt{128} [/tex]
[tex] = {2}^{2} \sqrt{2} - \sqrt{2} + {2}^{3} \sqrt{2} [/tex]
[tex] = 4 \sqrt{2} - \sqrt{2} + 8 \sqrt{2} [/tex]
[tex] = 4 \sqrt{2} - 1 \sqrt{2} + 8 \sqrt{2} [/tex]
[tex] = (4 - 1 + 8) \sqrt{2} [/tex]
[tex] = 11 \sqrt{2} [/tex]
[tex]3. \: \sqrt{12} + \sqrt{75} - \sqrt{27} [/tex]
[tex] = 2 \sqrt{3} + 5 \sqrt{3} - 3 \sqrt{3} [/tex]
[tex] = (2 + 5 - 3) \sqrt{3} [/tex]
[tex] = 4 \sqrt{3} [/tex]
[tex]4. \: {4}^{ - 1} + {3}^{ - 2} - {2}^{ - 3} [/tex]
[tex] = \frac{1}{4} + \frac{1}{ {3}^{2} } - \frac{1}{ {2}^{3} } [/tex]
[tex] = \frac{1}{4} + \frac{1}{9} - \frac{1}{8} [/tex]
[tex] = \frac{17}{72} [/tex]
[answer.2.content]
